设X(来学网),X…X。为来自正态总体N(0,0.3)的样本,则P{>1.44}(  )。
  • A.
    (来学网)0.9
  • B.
    (来学网)0.1
  • C.
    (来学网)0.2
  • D.
    (来学网)0.3
正确答案:
B
答案解析:
x]~N(0,0.3),x/0.3~N(0,1),χ=(x/0.3)~X(10),从而P{>1.44}=P{(x/0.3)>16}=P{χ>16)=0.1